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Indefinite Integrals question

2019 · 12 Apr · Shift 2 · Q26
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  5. /2019 · 12 Apr · Shift 2 · Q26

Indefinite Integrals question

2019 · 12 Apr · Shift 2 · Q26

JEE MainMathematicsIndefinite IntegralsMCQ+4 / −1
Let a∈(0,π2)a \in \left( {0,{\pi \over 2}} \right)a∈(0,2π​) be fixed. If the integral ∫tan⁡x+tan⁡αtan⁡x−tan⁡αdx\int {{{\tan x + \tan \alpha } \over {\tan x - \tan \alpha }}} dx∫tanx−tanαtanx+tanα​dx = A(x) cos 2 α\alphaα + B(x) sin 2 α\alphaα + C, where C is a constant of integration, then the functions A(x) and B(x) are respectively :
  1. A
    x−αx - \alphax−α and log⁡e∣cos⁡(x−α)∣{\log _e}\left| {\cos \left( {x - \alpha } \right)} \right|loge​∣cos(x−α)∣
  2. B
    x+αx + \alphax+α and log⁡e∣sin⁡(x−α)∣{\log _e}\left| {\sin \left( {x - \alpha } \right)} \right|loge​∣sin(x−α)∣
  3. C
    x+αx + \alphax+α and log⁡e∣sin⁡(x+α)∣{\log _e}\left| {\sin \left( {x + \alpha } \right)} \right|loge​∣sin(x+α)∣
  4. D
    x−αx - \alphax−α and log⁡e∣sin⁡(x−α)∣{\log _e}\left| {\sin \left( {x - \alpha } \right)} \right|loge​∣sin(x−α)∣
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