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Indefinite Integrals question

2018 · 15 Apr · Shift 2 · Q38

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PYQ Library
JEE Main
Mathematics
Indefinite Integrals
2018 · 15 Apr · Shift 2 · Q38

Indefinite Integrals question

2018 · 15 Apr · Shift 2 · Q38

JEE MainMathematicsIndefinite IntegralsMCQ+4 / −1

If

\int {{{2x + 5} \over {\sqrt {7 - 6x - {x^2}} }}} \,\,dx = A\sqrt {7 - 6x - {x^2}} + B{\sin ^{ - 1}}\left( {{{x + 3} \over 4}} \right) + C

(where C is a constant of integration), then the ordered pair (A, B) is equal to :

A
(2, 1)
B
( $-$ 2, $-$ 1)
C
( $-$ 2, 1)
D
(2, $-$ 1)

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