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Hyperbola question

2025 · 7 Apr · Shift 1 · Q50
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  5. /2025 · 7 Apr · Shift 1 · Q50

Hyperbola question

2025 · 7 Apr · Shift 1 · Q50

JEE MainMathematicsHyperbolaNumerical+4 / −1
Consider the hyperbola x2a2−y2b2=1\frac{x^2}{a^2}-\frac{y^2}{b^2}=1a2x2​−b2y2​=1 having one of its focus at P(−3,0)\mathrm{P}(-3,0)P(−3,0). If the latus ractum through its other focus subtends a right angle at P and a2b2=α2−β,α,β∈Na^2 b^2=\alpha \sqrt{2}-\beta, \alpha, \beta \in \mathbb{N}a2b2=α2​−β,α,β∈N, then α+β\alpha+\betaα+β is ‾\underline{\hspace{2cm}}​ .
Numerical answer
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