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Hyperbola question

2025 · 2 Apr · Shift 1 · Q35

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JEE Main
Mathematics
Hyperbola
2025 · 2 Apr · Shift 1 · Q35

Hyperbola question

2025 · 2 Apr · Shift 1 · Q35

JEE MainMathematicsHyperbolaMCQ+4 / −1

Let one focus of the hyperbola

\mathrm{H}: \frac{x^2}{\mathrm{a}^2}-\frac{y^2}{\mathrm{~b}^2}=1

be at

(\sqrt{10}, 0)

and the corresponding directrix be

x=\frac{9}{\sqrt{10}}

. If

e

and

l

respectively are the eccentricity and the length of the latus rectum of H , then

9\left(e^2+l\right)

is equal to :

A
12
B
14
C
15
D
16

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