JEE MainMathematicsHyperbolaMCQ+4 / −1
The locus of the midpoints of the chord of the circle, x2 + y2 = 25 which is tangent to the hyperbola, is :
- A(x2 + y2)2 9x2 + 16y2 = 0
- B(x2 + y2)2 9x2 + 144y2 = 0
- C(x2 + y2)2 16x2 + 9y2 = 0
- D(x2 + y2)2 9x2 16y2 = 0
View written solutionFree
Correct answer: A
-
Let the midpoint of the chord be .
For the circle the chord whose midpoint is has equation
This is the standard chord-with-given-midpoint form for the circle .
-
This chord is tangent to the hyperbola
So the line must be a tangent to the hyperbola.
-
Use the tangent condition for the hyperbola.
For the hyperbola a line is tangent iff
Here,
Therefore,
-
Hence the locus of is
Replacing by , the locus is
-
Match with the options.
This is exactly Option A:
Verification with stored answer
Stored correct answer: A
Our derived answer: A
So they agree.
More from Hyperbola
- The locus of the point of intersection of the lines and is a conic, whose eccentricity is .2021 · Numerical
- A hyperbola passes through the foci of the ellipse and its transverse and conjugate axes coincide with major and minor axes of the ellipse, respectively. If the product of their…2021 · MCQ
- The locus of the centroid of the triangle formed by any point P on the hyperbola , and its foci is :2021 · MCQ
- The locus of the mid points of the chords of the hyperbola x2 y2 = 4, which touch the parabola y2 = 8x, is :2021 · MCQ
- For some , if the eccentricity of the hyperbola, x2–y2sec2 = 10 is times the eccentricity of the ellipse, x2sec2 + y2 = 5, then the length of the latus rectum of the…2020 · MCQ
- A hyperbola having the transverse axis of length has the same foci as that of the ellipse 3x2 + 4y2 = 12, then this hyperbola does not pass through which of the following points?2020 · MCQ
- Let e1 and e2 be the eccentricities of the ellipse, (b < 5) and the hyperbola, respectively satisfying e1e2 = 1. If and …2020 · MCQ
- If e1 and e2 are the eccentricities of the ellipse, and the hyperbola, respectively and (e1, e2) is a point on the ellipse, 15x2 + 3y2 = k, then k…2020 · MCQ