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Hyperbola question

2020 · 9 Jan · Shift 1 · Q40
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  5. /2020 · 9 Jan · Shift 1 · Q40

Hyperbola question

2020 · 9 Jan · Shift 1 · Q40

JEE MainMathematicsHyperbolaMCQ+4 / −1
If e1 and e2 are the eccentricities of the ellipse, x218+y24=1{{{x^2}} \over {18}} + {{{y^2}} \over 4} = 118x2​+4y2​=1 and the hyperbola, x29−y24=1{{{x^2}} \over 9} - {{{y^2}} \over 4} = 19x2​−4y2​=1 respectively and (e1, e2) is a point on the ellipse, 15x2 + 3y2 = k, then k is equal to :
  1. A
    17
  2. B
    16
  3. C
    15
  4. D
    14
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