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Functions question

2022 · 27 Jun · Shift 1 · Q36
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  5. /2022 · 27 Jun · Shift 1 · Q36

Functions question

2022 · 27 Jun · Shift 1 · Q36

JEE MainMathematicsFunctionsNumerical+4 / −1
Let f : R →\to→ R be a function defined by f(x)=2e2xe2x+ef(x) = {{2{e^{2x}}} \over {{e^{2x}} + e}}f(x)=e2x+e2e2x​. Then f(1100)+f(2100)+f(3100)+   .....   +   f(99100)f\left( {{1 \over {100}}} \right) + f\left( {{2 \over {100}}} \right) + f\left( {{3 \over {100}}} \right) + \,\,\,.....\,\,\, + \,\,\,f\left( {{{99} \over {100}}} \right)f(1001​)+f(1002​)+f(1003​)+.....+f(10099​) is equal to ‾\underline{\hspace{2cm}}​.
Numerical answer
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