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Functions question

2022 · 29 Jun · Shift 1 · Q39
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  5. /2022 · 29 Jun · Shift 1 · Q39

Functions question

2022 · 29 Jun · Shift 1 · Q39

JEE MainMathematicsFunctionsNumerical+4 / −1
Let c, k ∈\in∈ R. If f(x)=(c+1)x2+(1−c2)x+2kf(x) = (c + 1){x^2} + (1 - {c^2})x + 2kf(x)=(c+1)x2+(1−c2)x+2k and f(x+y)=f(x)+f(y)−xyf(x + y) = f(x) + f(y) - xyf(x+y)=f(x)+f(y)−xy, for all x, y ∈\in∈ R, then the value of ∣2(f(1)+f(2)+f(3)+  ......  +  f(20))∣|2(f(1) + f(2) + f(3) + \,\,......\,\, + \,\,f(20))|∣2(f(1)+f(2)+f(3)+......+f(20))∣ is equal to ‾\underline{\hspace{2cm}}​.
Numerical answer
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