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Ellipse question

2025 · 3 Apr · Shift 2 · Q30
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Ellipse question

2025 · 3 Apr · Shift 2 · Q30

JEE MainMathematicsEllipseMCQ+4 / −1
Let CCC be the circle of minimum area enclosing the ellipse E:x2a2+y2b2=1E: \frac{x^2}{a^2}+\frac{y^2}{b^2}=1E:a2x2​+b2y2​=1 with eccentricity 12\frac{1}{2}21​ and foci (±2,0)( \pm 2,0)(±2,0). Let PQRP Q RPQR be a variable triangle, whose vertex PPP is on the circle CCC and the side QRQ RQR of length 2a2 a2a is parallel to the major axis of EEE and contains the point of intersection of EEE with the negative yyy-axis. Then the maximum area of the triangle PQRP Q RPQR is :
  1. A
    8(3+2)8(3+\sqrt{2})8(3+2​)
  2. B
    8(2+3)8(2+\sqrt{3})8(2+3​)
  3. C
    6(3+2)6(3+\sqrt{2})6(3+2​)
  4. D
    6(2+3)6(2+\sqrt{3})6(2+3​)
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