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Ellipse question

2022 · 24 Jun · Shift 2 · Q29
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  5. /2022 · 24 Jun · Shift 2 · Q29

Ellipse question

2022 · 24 Jun · Shift 2 · Q29

JEE MainMathematicsEllipseMCQ+4 / −1
Let the maximum area of the triangle that can be inscribed in the ellipse x2a2+y24=1, a>2{{{x^2}} \over {{a^2}}} + {{{y^2}} \over 4} = 1,\,a \gt 2a2x2​+4y2​=1,a>2, having one of its vertices at one end of the major axis of the ellipse and one of its sides parallel to the y-axis, be 636\sqrt 363​. Then the eccentricity of the ellipse is :
  1. A
    32{{\sqrt 3 } \over 2}23​​
  2. B
    12{1 \over 2}21​
  3. C
    12{1 \over {\sqrt 2 }}2​1​
  4. D
    34{{\sqrt 3 } \over 4}43​​
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