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Ellipse question

2009 · Shift 0 · Q38

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PYQ Library
JEE Main
Mathematics
Ellipse
2009 · Shift 0 · Q38

Ellipse question

2009 · Shift 0 · Q38

JEE MainMathematicsEllipseMCQ+4 / −1

The ellipse

{x^2} + 4{y^2} = 4

is inscribed in a rectangle aligned with the coordinate axex, which in turn is inscribed in another ellipse that passes through the point

(4,0)

. Then the equation of the ellipse is :

A
${x^2} + 12{y^2} = 16$
B
$4{x^2} + 48{y^2} = 48$
C
$4{x^2} + 64{y^2} = 48$
D
${x^2} + 16{y^2} = 16$

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