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Differentiation question

2024 · 30 Jan · Shift 1 · Q31
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  5. /2024 · 30 Jan · Shift 1 · Q31

Differentiation question

2024 · 30 Jan · Shift 1 · Q31

JEE MainMathematicsDifferentiationMCQ+4 / −1
Let g:R→Rg: \mathbf{R} \rightarrow \mathbf{R}g:R→R be a non constant twice differentiable function such that g′(12)=g′(32)\mathrm{g}^{\prime}\left(\frac{1}{2}\right)=\mathrm{g}^{\prime}\left(\frac{3}{2}\right)g′(21​)=g′(23​). If a real valued function fff is defined as f(x)=12[g(x)+g(2−x)]f(x)=\frac{1}{2}[g(x)+g(2-x)]f(x)=21​[g(x)+g(2−x)], then
  1. A
    f′′(x)=0f^{\prime \prime}(x)=0f′′(x)=0 for atleast two xxx in (0,2)(0,2)(0,2)
  2. B
    f′(32)+f′(12)=1f^{\prime}\left(\frac{3}{2}\right)+f^{\prime}\left(\frac{1}{2}\right)=1f′(23​)+f′(21​)=1
  3. C
    f′′(x)=0f^{\prime \prime}(x)=0f′′(x)=0 for no xxx in (0,1)(0,1)(0,1)
  4. D
    f′′(x)=0f^{\prime \prime}(x)=0f′′(x)=0 for exactly one xxx in (0,1)(0,1)(0,1)
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