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Differentiation question

2023 · 1 Feb · Shift 1 · Q30
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  5. /2023 · 1 Feb · Shift 1 · Q30

Differentiation question

2023 · 1 Feb · Shift 1 · Q30

JEE MainMathematicsDifferentiationMCQ+4 / −1
Let f(x)=2x+tan⁡−1xf(x) = 2x + {\tan ^{ - 1}}xf(x)=2x+tan−1x and g(x)=log⁡e(1+x2+x),x∈[0,3]g(x) = {\log _e}(\sqrt {1 + {x^2}} + x),x \in [0,3]g(x)=loge​(1+x2​+x),x∈[0,3]. Then
  1. A
    there exists x^∈[0,3]\widehat x \in [0,3]x∈[0,3] such that f′(x^)<g′(x^)f'(\widehat x) \lt g'(\widehat x)f′(x)<g′(x)
  2. B
    there exist 0<x1<x2<30 \lt {x_1} \lt {x_2} \lt 30<x1​<x2​<3 such that f(x)<g(x),∀x∈(x1,x2)f(x) \lt g(x),\forall x \in ({x_1},{x_2})f(x)<g(x),∀x∈(x1​,x2​)
  3. C
    min⁡f′(x)=1+max⁡g′(x)\min f'(x) = 1 + \max g'(x)minf′(x)=1+maxg′(x)
  4. D
    max⁡f(x)>max⁡g(x)\max f(x) \gt \max g(x)maxf(x)>maxg(x)
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