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Differentiation question

2022 · 27 Jul · Shift 2 · Q37
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  5. /2022 · 27 Jul · Shift 2 · Q37

Differentiation question

2022 · 27 Jul · Shift 2 · Q37

JEE MainMathematicsDifferentiationNumerical+4 / −1
For the curve C:(x2+y2−3)+(x2−y2−1)5=0C:\left(x^{2}+y^{2}-3\right)+\left(x^{2}-y^{2}-1\right)^{5}=0C:(x2+y2−3)+(x2−y2−1)5=0, the value of 3y′−y3y′′3 y^{\prime}-y^{3} y^{\prime \prime}3y′−y3y′′, at the point (α,α)(\alpha, \alpha)(α,α), α>0\alpha\gt 0α>0, on C, is equal to ‾\underline{\hspace{2cm}}​.
Numerical answer
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