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Differentiation question

2021 · 26 Aug · Shift 1 · Q27

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JEE Main
Mathematics
Differentiation
2021 · 26 Aug · Shift 1 · Q27

Differentiation question

2021 · 26 Aug · Shift 1 · Q27

JEE MainMathematicsDifferentiationMCQ+4 / −1

Let

f(x) = \cos \left( {2{{\tan }^{ - 1}}\sin \left( {{{\cot }^{ - 1}}\sqrt {{{1 - x} \over x}} } \right)} \right)

, 0 < x < 1. Then :

A
${(1 - x)^2}f'(x) - 2{(f(x))^2} = 0$
B
${(1 + x)^2}f'(x) + 2{(f(x))^2} = 0$
C
${(1 - x)^2}f'(x) + 2{(f(x))^2} = 0$
D
${(1 + x)^2}f'(x) - 2{(f(x))^2} = 0$

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