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Differentiation question

2019 · 12 Jan · Shift 1 · Q41

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PYQ Library
JEE Main
Mathematics
Differentiation
2019 · 12 Jan · Shift 1 · Q41

Differentiation question

2019 · 12 Jan · Shift 1 · Q41

JEE MainMathematicsDifferentiationMCQ+4 / −1

For x > 1, if (2x)2y = 4e2x

-

2y, then (1 + loge 2x)2

{{dy} \over {dx}}

is equal to :

A
${{x\,{{\log }_e}2x - {{\log }_e}2} \over x}$
B
loge 2x
C
x loge 2x
D
${{x\,{{\log }_e}2x + {{\log }_e}2} \over x}$

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