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Differentiation question

2017 · Shift 0 · Q42

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PYQ Library
JEE Main
Mathematics
Differentiation
2017 · Shift 0 · Q42

Differentiation question

2017 · Shift 0 · Q42

JEE MainMathematicsDifferentiationMCQ+4 / −1

If for

x \in \left( {0,{1 \over 4}} \right)

, the derivatives of

{\tan ^{ - 1}}\left( {{{6x\sqrt x } \over {1 - 9{x^3}}}} \right)

is

\sqrt x .g\left( x \right)

, then

g\left( x \right)

equals

A
${{{3x\sqrt x } \over {1 - 9{x^3}}}}$
B
${{{3x} \over {1 - 9{x^3}}}}$
C
${{3 \over {1 + 9{x^3}}}}$
D
${{9 \over {1 + 9{x^3}}}}$

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