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Differential Equations question

2024 · 29 Jan · Shift 1 · Q60
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  5. /2024 · 29 Jan · Shift 1 · Q60

Differential Equations question

2024 · 29 Jan · Shift 1 · Q60

JEE MainMathematicsDifferential EquationsNumerical+4 / −1
If the solution curve y=y(x)y=y(x)y=y(x) of the differential equation (1+y2)(1+log⁡ex)dx+xdy=0,x>0\left(1+y^2\right)\left(1+\log _{\mathrm{e}} x\right) d x+x d y=0, x \gt 0(1+y2)(1+loge​x)dx+xdy=0,x>0 passes through the point (1,1)(1,1)(1,1) and y(e)=α−tan⁡(32)β+tan⁡(32)y(e)=\frac{\alpha-\tan \left(\frac{3}{2}\right)}{\beta+\tan \left(\frac{3}{2}\right)}y(e)=β+tan(23​)α−tan(23​)​, then α+2β\alpha+2 \betaα+2β is ‾\underline{\hspace{2cm}}​.
Numerical answer
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