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Differential Equations question

2023 · 29 Jan · Shift 2 · Q24
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  5. /2023 · 29 Jan · Shift 2 · Q24

Differential Equations question

2023 · 29 Jan · Shift 2 · Q24

JEE MainMathematicsDifferential EquationsMCQ+4 / −1
Let y=y(x)y=y(x)y=y(x) be the solution of the differential equation xlog⁡exdydx+y=x2log⁡ex,(x>1)x{\log _e}x{{dy} \over {dx}} + y = {x^2}{\log _e}x,(x \gt 1)xloge​xdxdy​+y=x2loge​x,(x>1). If y(2)=2y(2) = 2y(2)=2, then y(e)y(e)y(e) is equal to
  1. A
    1+e22{{1 + {e^2}} \over 2}21+e2​
  2. B
    1+e24{{1 + {e^2}} \over 4}41+e2​
  3. C
    2+e22{{2 + {e^2}} \over 2}22+e2​
  4. D
    4+e24{{4 + {e^2}} \over 4}44+e2​
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