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Differential Equations question

2022 · 25 Jul · Shift 1 · Q31

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JEE Main
Mathematics
Differential Equations
2022 · 25 Jul · Shift 1 · Q31

Differential Equations question

2022 · 25 Jul · Shift 1 · Q31

JEE MainMathematicsDifferential EquationsMCQ+4 / −1

The general solution of the differential equation

\left(x-y^{2}\right) \mathrm{d} x+y\left(5 x+y^{2}\right) \mathrm{d} y=0

is :

A
$\left(y^{2}+x\right)^{4}=\mathrm{C}\left|\left(y^{2}+2 x\right)^{3}\right|$
B
$\left(y^{2}+2 x\right)^{4}=C\left|\left(y^{2}+x\right)^{3}\right|$
C
$\left|\left(y^{2}+x\right)^{3}\right|=\mathrm{C}\left(2 y^{2}+x\right)^{4}$
D
$\left|\left(y^{2}+2 x\right)^{3}\right|=C\left(2 y^{2}+x\right)^{4}$

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