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Differential Equations question

2023 · 24 Jan · Shift 1 · Q29
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  5. /2023 · 24 Jan · Shift 1 · Q29

Differential Equations question

2023 · 24 Jan · Shift 1 · Q29

JEE MainMathematicsDifferential EquationsMCQ+4 / −1
Let y=y(x)y = y(x)y=y(x) be the solution of the differential equation x3dy+(xy−1)dx=0,x>0,y(12)=3−e{x^3}dy + (xy - 1)dx = 0,x \gt 0,y\left( {{1 \over 2}} \right) = 3 - \mathrm{e}x3dy+(xy−1)dx=0,x>0,y(21​)=3−e. Then y (1) is equal to
  1. A
    2 −-− e
  2. B
    3
  3. C
    1
  4. D
    e
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