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Differential Equations question

2023 · 13 Apr · Shift 2 · Q41
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  5. /2023 · 13 Apr · Shift 2 · Q41

Differential Equations question

2023 · 13 Apr · Shift 2 · Q41

JEE MainMathematicsDifferential EquationsNumerical+4 / −1
If y=y(x)y=y(x)y=y(x) is the solution of the differential equation dydx+4x(x2−1)y=x+2(x2−1)52,x>1\frac{d y}{d x}+\frac{4 x}{\left(x^{2}-1\right)} y=\frac{x+2}{\left(x^{2}-1\right)^{\frac{5}{2}}}, x \gt 1dxdy​+(x2−1)4x​y=(x2−1)25​x+2​,x>1 such that y(2)=29log⁡e(2+3) and y(2)=αlog⁡e(α+β)+β−γ,α,β,γ∈N, then αβγ is equal to y(2)=\frac{2}{9} \log _{e}(2+\sqrt{3}) \text { and } y(\sqrt{2})=\alpha \log _{e}(\sqrt{\alpha}+\beta)+\beta-\sqrt{\gamma}, \alpha, \beta, \gamma \in \mathbb{N} \text {, then } \alpha \beta \gamma \text { is equal to }y(2)=92​loge​(2+3​) and y(2​)=αloge​(α​+β)+β−γ​,α,β,γ∈N, then αβγ is equal to  :
Numerical answer
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