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Differential Equations question

2021 · 20 Jul · Shift 1 · Q32
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  5. /2021 · 20 Jul · Shift 1 · Q32

Differential Equations question

2021 · 20 Jul · Shift 1 · Q32

JEE MainMathematicsDifferential EquationsMCQ+4 / −1
Let y = y(x) be the solution of the differential equation ex1−y2dx+(yx)dy=0{e^x}\sqrt {1 - {y^2}} dx + \left( {{y \over x}} \right)dy = 0ex1−y2​dx+(xy​)dy=0, y(1) = −-− 1. Then the value of (y(3))2 is equal to :
  1. A
    1 −-− 4e3
  2. B
    1 −-− 4e6
  3. C
    1 + 4e3
  4. D
    1 + 4e6
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