JEE MainMathematicsDefinite IntegrationNumerical+4 / −1If ∫−0.150.15∣100x2−1∣dx=k3000\int_{-0.15}^{0.15}\left|100 x^{2}-1\right| d x=\frac{k}{3000}∫−0.150.15100x2−1dx=3000k, then kkk is equal to ‾\underline{\hspace{2cm}}.Numerical answerAttempt in chatSharePreviousNextMore from Definite Integration∫0∞e3x+6e2x+11ex+66dx=2023 · MCQLet for x∈R,S0(x)=x,Sk(x)=Ckx+k∫0xSk−1(t)dt, where C0=1,Ck=1−∫01Sk−1(x)dx,k=1,2,3,… Then S2(3)+6C3 is equal to .2023 · NumericalThe value of 0∫4πe−x(tan49x+tan51x)dxe−4π+0∫4πe−xtan50xdx is2023 · MCQLet fn=∫02π(∑k=1nsink−1x)(∑k=1n(2k−1)sink−1x)cosxdx,n∈N. Then f21−f20 is equal to 2023 · NumericalIf 0∫1(5+2x−2x2)(1+e(2−4x))1dx=α1loge(βα+1),α,β>0, then α4−β4 is equal to :2023 · MCQThe value of 120∫3x2−3x+2dx is 2023 · NumericalThe value of π80∫2π(sinx)2023+(cosx)2023(cosx)2023dx is 2023 · Numerical432∫4339−4x248dx is equal to :2023 · MCQ