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Definite Integration question

2022 · 28 Jun · Shift 1 · Q28
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  5. /2022 · 28 Jun · Shift 1 · Q28

Definite Integration question

2022 · 28 Jun · Shift 1 · Q28

JEE MainMathematicsDefinite IntegrationMCQ+4 / −1
Let [t] denote the greatest integer less than or equal to t. Then, the value of the integral ∫01[−8x2+6x−1]dx\int\limits_0^1 {[ - 8{x^2} + 6x - 1]dx}0∫1​[−8x2+6x−1]dx is equal to :
  1. A
    −-− 1
  2. B
    −54{{ - 5} \over 4}4−5​
  3. C
    17−138{{\sqrt {17} - 13} \over 8}817​−13​
  4. D
    17−168{{\sqrt {17} - 16} \over 8}817​−16​
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