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Definite Integration question

2021 · 16 Mar · Shift 1 · Q38
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  5. /2021 · 16 Mar · Shift 1 · Q38

Definite Integration question

2021 · 16 Mar · Shift 1 · Q38

JEE MainMathematicsDefinite IntegrationNumerical+4 / −1
Let f : R →\to→ R be a continuous function such that f(x) + f(x + 1) = 2, for all x ∈\in∈ R. If I1=∫08f(x)dx{I_1} = \int\limits_0^8 {f(x)dx}I1​=0∫8​f(x)dx and I2=∫−13f(x)dx{I_2} = \int\limits_{ - 1}^3 {f(x)dx}I2​=−1∫3​f(x)dx, then the value of I1 + 2I2 is equal to ‾\underline{\hspace{2cm}}​.
Numerical answer
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