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Definite Integration question

2018 · 15 Apr · Shift 2 · Q39
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  5. /2018 · 15 Apr · Shift 2 · Q39

Definite Integration question

2018 · 15 Apr · Shift 2 · Q39

JEE MainMathematicsDefinite IntegrationMCQ+4 / −1
If I1=∫01e−xcos⁡2x dx;I2=∫01e−x2cos⁡2x dx{I_1} = \int_0^1 {{e^{ - x}}} {\cos ^2}x{\mkern 1mu} dx;{I_2} = \int_0^1 {{e^{ - {x^2}}}} {\cos ^2}x{\mkern 1mu} dxI1​=∫01​e−xcos2xdx;I2​=∫01​e−x2cos2xdx and I3=∫01e−x3dx;{I_3} = \int_0^1 {{e^{ - {x^3}}}} dx;I3​=∫01​e−x3dx; then
  1. A
    I2 > I3 > I1
  2. B
    I2 > I1 > I3
  3. C
    I3 > I2 > I1
  4. D
    I3 > I1 > I2
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