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Complex Numbers question

2025 · 2 Apr · Shift 1 · Q34
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  5. /2025 · 2 Apr · Shift 1 · Q34

Complex Numbers question

2025 · 2 Apr · Shift 1 · Q34

JEE MainMathematicsComplex NumbersMCQ+4 / −1
Let zzz be a complex number such that ∣z∣=1|z|=1∣z∣=1. If 2+k2zk+zˉ=kz,k∈R\frac{2+\mathrm{k}^2 z}{\mathrm{k}+\bar{z}}=\mathrm{k} z, \mathrm{k} \in \mathbf{R}k+zˉ2+k2z​=kz,k∈R, then the maximum distance of k+ik2\mathrm{k}+i \mathrm{k}^2k+ik2 from the circle ∣z−(1+2i)∣=1|z-(1+2 i)|=1∣z−(1+2i)∣=1 is :
  1. A
    5+1\sqrt{5}+15​+1
  2. B
    3
  3. C
    3+1\sqrt{3}+13​+1
  4. D
    2
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