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Complex Numbers question

2005 · Shift 0 · Q70

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PYQ Library
JEE Main
Mathematics
Complex Numbers
2005 · Shift 0 · Q70

Complex Numbers question

2005 · Shift 0 · Q70

JEE MainMathematicsComplex NumbersMCQ+4 / −1

If the cube roots of unity are 1,

\omega \,,\,{\omega ^2}

then the roots of the equation

{(x - 1)^3}

+ 8 = 0, are :

A
$- 1, - 1 + 2\,\,\omega , - 1 - 2\,\,{\omega ^2}$
B
$- 1, - 1, - 1$
C
$- 1,1 - 2\omega ,1 - 2{\omega ^2}$
D
$- 1,1 + 2\omega ,1 + 2{\omega ^2}$

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