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Circle question

2024 · 9 Apr · Shift 1 · Q40
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  5. /2024 · 9 Apr · Shift 1 · Q40

Circle question

2024 · 9 Apr · Shift 1 · Q40

JEE MainMathematicsCircleMCQ+4 / −1
Let a circle passing through (2,0)(2,0)(2,0) have its centre at the point (h,k)(\mathrm{h}, \mathrm{k})(h,k). Let (xc,yc)(x_{\mathrm{c}}, y_{\mathrm{c}})(xc​,yc​) be the point of intersection of the lines 3x+5y=13 x+5 y=13x+5y=1 and (2+c)x+5c2y=1(2+\mathrm{c}) x+5 \mathrm{c}^2 y=1(2+c)x+5c2y=1. If h=lim⁡c→1xc\mathrm{h}=\lim_{\mathrm{c} \rightarrow 1} x_{\mathrm{c}}h=c→1lim​xc​ and k=lim⁡c→1yc\mathrm{k}=\lim_{\mathrm{c} \rightarrow 1} y_{\mathrm{c}}k=c→1lim​yc​, then the equation of the circle is :
  1. A
    5x2+5y2−4x−2y−12=05 x^2+5 y^2-4 x-2 y-12=05x2+5y2−4x−2y−12=0
  2. B
    25x2+25y2−20x+2y−60=025 x^2+25 y^2-20 x+2 y-60=025x2+25y2−20x+2y−60=0
  3. C
    25x2+25y2−2x+2y−60=025 x^2+25 y^2-2 x+2 y-60=025x2+25y2−2x+2y−60=0
  4. D
    5x2+5y2−4x+2y−12=05 x^2+5 y^2-4 x+2 y-12=05x2+5y2−4x+2y−12=0
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