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Circle question

2024 · 27 Jan · Shift 2 · Q58
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  5. /2024 · 27 Jan · Shift 2 · Q58

Circle question

2024 · 27 Jan · Shift 2 · Q58

JEE MainMathematicsCircleNumerical+4 / −1
Consider a circle (x−α)2+(y−β)2=50(x-\alpha)^2+(y-\beta)^2=50(x−α)2+(y−β)2=50, where α,β>0\alpha, \beta\gt 0α,β>0. If the circle touches the line y+x=0y+x=0y+x=0 at the point PPP, whose distance from the origin is 424 \sqrt{2}42​, then (α+β)2(\alpha+\beta)^2(α+β)2 is equal to ‾\underline{\hspace{2cm}}​.
Numerical answer
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