JEE MainMathematicsCircleMCQ+4 / −1
If the image of the point in the line lies on the circle , then is equal to:
- A2
- B3
- C4
- D1
View written solutionFree
Correct answer: A
- Given data
- Point:
- Mirror line: , i.e.
- Circle:
We need the image of in the line , and that image lies on the circle.
- Reflection formula
For a point reflected in the line the image is
Here,
First compute:
Also,
So the reflected point is
=\left(-4-\frac{8}{5},\;5-\frac{16}{5}\right) =\left(-\frac{28}{5},\;\frac{9}{5}\right).$$ Let this image be $P'\left(-\frac{28}{5},\frac{9}{5}\right)$. --- 3. **Use the circle equation** The circle is $$(x+4)^2+(y-3)^2=r^2,$$ so its center is $$(-4,3).$$ Since $P'$ lies on the circle, $$r^2=\left(-\frac{28}{5}+4\right)^2+\left(\frac{9}{5}-3\right)^2.$$ Now simplify: $$-\frac{28}{5}+4=-\frac{28}{5}+\frac{20}{5}=-\frac{8}{5},$$ $$\frac{9}{5}-3=\frac{9}{5}-\frac{15}{5}=-\frac{6}{5}.$$ Thus, $$r^2=\left(-\frac{8}{5}\right)^2+\left(-\frac{6}{5}\right)^2 =\frac{64}{25}+\frac{36}{25} =\frac{100}{25}=4.$$ Therefore, $$r=2.$$ --- 4. **Check options** - A: $2$ ✅ - B: $3$ ❌ - C: $4$ ❌ - D: $1$ ❌ So the correct option is **A**.More from Circle
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