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Circle question

2006 · Shift 0 · Q78
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Circle question

2006 · Shift 0 · Q78

JEE MainMathematicsCircleMCQ+4 / −1
If the lines 3x−4y−7=03x - 4y - 7 = 03x−4y−7=0 and 2x−3y−5=02x - 3y - 5 = 02x−3y−5=0 are two diameters of a circle of area 49π49\pi49π square units, the equation of the circle is :
  1. A
     x2+y2+2x −2y−47=0 \,{x^2} + {y^2} + 2x\, - 2y - 47 = 0\,x2+y2+2x−2y−47=0
  2. B
     x2+y2+2x −2y−62=0 \,{x^2} + {y^2} + 2x\, - 2y - 62 = 0\,x2+y2+2x−2y−62=0
  3. C
    x2+y2−2x +2y−62=0{x^2} + {y^2} - 2x\, + 2y - 62 = 0x2+y2−2x+2y−62=0
  4. D
    x2+y2−2x +2y−47=0{x^2} + {y^2} - 2x\, + 2y - 47 = 0x2+y2−2x+2y−47=0
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