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Circle question

2003 · Shift 0 · Q113
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Circle question

2003 · Shift 0 · Q113

JEE MainMathematicsCircleMCQ+4 / −1
The lines 2x - 3y = 5 and 3x - 4y = 7 are diameters of a circle having area as 154 sq. units. Then the equation of the circle is :
  1. A
    x2 + y2− 2x + 2y  = 62{x^2}\, + \,{y^2} - \,2x\, + \,2y\,\, = \,62x2+y2−2x+2y=62
  2. B
    x2 + y2+ 2x − 2y  = 62{x^2}\, + \,{y^2} + \,2x\, - \,2y\,\, = \,62x2+y2+2x−2y=62
  3. C
    x2 + y2+ 2x − 2y  = 47{x^2}\, + \,{y^2} + \,2x\, - \,2y\,\, = \,47x2+y2+2x−2y=47
  4. D
    x2 + y2− 2x + 2y  = 47{x^2}\, + \,{y^2} - \,2x\, + \,2y\,\, = \,47x2+y2−2x+2y=47
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