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Circle question

2005 · Shift 0 · Q106

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PYQ Library
JEE Main
Mathematics
Circle
2005 · Shift 0 · Q106

Circle question

2005 · Shift 0 · Q106

JEE MainMathematicsCircleMCQ+4 / −1

If the pair of lines

a{x^2} + 2\left( {a + b} \right)xy + b{y^2} = 0

lie along diameters of a circle and divide the circle into four sectors such that the area of one of the sectors is thrice the area of another sector then :

A
$3{a^2} - 10ab + 3{b^2} = 0$
B
$3{a^2} - 2ab + 3{b^2} = 0$
C
$3{a^2} + 10ab + 3{b^2} = 0$
D
$3{a^2} + 2ab + 3{b^2} = 0$

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