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Binomial Theorem question

2024 · 1 Feb · Shift 2 · Q49
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  5. /2024 · 1 Feb · Shift 2 · Q49

Binomial Theorem question

2024 · 1 Feb · Shift 2 · Q49

JEE MainMathematicsBinomial TheoremMCQ+4 / −1
Let mmm and nnn be the coefficients of seventh and thirteenth terms respectively in the expansion of (13x13+12x23)18\left(\frac{1}{3} x^{\frac{1}{3}}+\frac{1}{2 x^{\frac{2}{3}}}\right)^{18}(31​x31​+2x32​1​)18. Then (nm)13\left(\frac{\mathrm{n}}{\mathrm{m}}\right)^{\frac{1}{3}}(mn​)31​ is :
  1. A
    19\frac{1}{9}91​
  2. B
    14\frac{1}{4}41​
  3. C
    49\frac{4}{9}94​
  4. D
    94\frac{9}{4}49​
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