New chat PYQ Library Doubts Rank report

Sign in to see Recents

Sign in to save progress →

3D Geometry question

2021 · 25 Feb · Shift 1 · Q25

Guest · try one question or challengeGuest · try one question or challenge

PYQ Library
JEE Main
Mathematics
3D Geometry
2021 · 25 Feb · Shift 1 · Q25

3D Geometry question

2021 · 25 Feb · Shift 1 · Q25

JEE MainMathematics3D GeometryMCQ+4 / −1

The equation of the line through the point (0, 1, 2) and perpendicular to the line

{{x - 1} \over 2} = {{y + 1} \over 3} = {{z - 1} \over { - 2}}

is :

A
${x \over 3} = {{y - 1} \over { - 4}} = {{z - 2} \over 3}$
B
${x \over 3} = {{y - 1} \over 4} = {{z - 2} \over { - 3}}$
C
${x \over { - 3}} = {{y - 1} \over 4} = {{z - 2} \over 3}$
D
${x \over 3} = {{y - 1} \over 4} = {{z - 2} \over 3}$

More from 3D Geometry

Let $α$ be the angle between the lines whose direction cosines satisfy the equations l + m $-$ n = 0 and l2 + m2 $-$ n2 = 0. Then the value of sin4 $α$ + cos4 $α$ is :2021 · MCQ
A line 'l' passing through origin is perpendicular to the lines $l_{1} : r = (3 + t) i + (- 1 + 2 t) j + (4 + 2 t) k l_{2} : r = (3 + 2 s) i + (3 + 2 s) j + (2 + s) k$ …2021 · Numerical
The angle between the straight lines, whose direction cosines are given by the equations 2l + 2m $-$ n = 0 and mn + nl + lm = 0, is :2021 · MCQ
If (a, b, c) is the image of the point (1, 2, -3) in the line $\frac{x + 1}{2} = \frac{y - 3}{- 2} = \frac{z}{- 1}$ , then a + b + c is :2020 · MCQ
If the foot of the perpendicular drawn from the point (1, 0, 3) on a line passing through ( $α$ , 7, 1) is $(\frac{5}{3}, \frac{7}{3}, \frac{17}{3})$ , then $α$ is equal to .2020 · Numerical
The shortest distance between the lines $\frac{x - 3}{3} = \frac{y - 8}{- 1} = \frac{z - 3}{1}$ and $\frac{x + 3}{- 3} = \frac{y + 7}{2} = \frac{z - 6}{4}$ is :2020 · MCQ
The projection of the line segment joining the points (1, –1, 3) and (2, –4, 11) on the line joining the points (–1, 2, 3) and (3, –2, 10) is .2020 · Numerical
The length of the perpendicular from the point (2, –1, 4) on the straight line, $\frac{x + 3}{10}$ = $\frac{y - 2}{- 7}$ = $\frac{z}{1}$ is :2019 · MCQ