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3D Geometry question

2021 · 16 Mar · Shift 2 · Q27
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  5. /2021 · 16 Mar · Shift 2 · Q27

3D Geometry question

2021 · 16 Mar · Shift 2 · Q27

JEE MainMathematics3D GeometryMCQ+4 / −1
If the foot of the perpendicular from point (4, 3, 8) on the line L1:x−al=y−23=z−b4{L_1}:{{x - a} \over l} = {{y - 2} \over 3} = {{z - b} \over 4}L1​:lx−a​=3y−2​=4z−b​, l eee 0 is (3, 5, 7), then the shortest distance between the line L1 and line L2:x−23=y−44=z−55{L_2}:{{x - 2} \over 3} = {{y - 4} \over 4} = {{z - 5} \over 5}L2​:3x−2​=4y−4​=5z−5​ is equal to :
  1. A
    16{1 \over {\sqrt 6 }}6​1​
  2. B
    12{1 \over 2}21​
  3. C
    13{1 \over {\sqrt 3 }}3​1​
  4. D
    23\sqrt {{2 \over 3}}32​​
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