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Thermodynamics question

2025 · 8 Apr · Shift 2 · Q25
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Thermodynamics question

2025 · 8 Apr · Shift 2 · Q25

JEE MainChemistryThermodynamicsNumerical+4 / −1
Resonance in X2Y\mathrm{X}_2 \mathrm{Y}X2​Y can be represented as JEE Main 2025 (Online) 8th April Evening Shift Chemistry - Thermodynamics Question 13 English The enthalpy of formation of X2Y(X=X(g)+12Y=Y(g)→X2Y(g))X_2Y \left(X = X(g) + \frac{1}{2} Y = Y(g) \rightarrow X_2Y(g) \right)X2​Y(X=X(g)+21​Y=Y(g)→X2​Y(g)) is 80 kJ mol −1^{-1}−1. The magnitude of resonance energy of X2YX_2YX2​Y is __ kJ mol −1^{-1}−1(nearest integer value). Given: Bond energies of X≡XX \equiv XX≡X, X=XX = XX=X, Y=YY = YY=Y and X=YX = YX=Y are 940, 410, 500, and 602 kJ mol −1^{-1}−1 respectively. valence XXX: 3, YYY: 2
Numerical answer
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