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Thermodynamics question

2021 · 27 Jul · Shift 2 · Q14
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Thermodynamics question

2021 · 27 Jul · Shift 2 · Q14

JEE MainChemistryThermodynamicsNumerical+4 / −1
When 400 mL of 0.2 M H2SO4H_2SO_4H2​SO4​ solution is mixed with 600 mL of 0.1 M NaOHNaOHNaOH solution, the increase in temperature of the final solution is ‾×\underline{\hspace{2cm}}\times​× 10 −-− 2 K. (Round off to the nearest integer). [Use : H+H^+H+ (aq) + OH −-−(aq) →\to→ H2OH_2OH2​O : Δγ\Delta\gammaΔγ H = −-− 57.1 kJ mol −-− 1] Specific heat of H2OH_2OH2​O = 4.18 J K −-− 1 g −-− 1 density of H2OH_2OH2​O = 1.0 g cm −-− 3 Assume no change in volume of solution on mixing.
Numerical answer
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