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Thermodynamics question

2021 · 27 Jul · Shift 1 · Q20
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Thermodynamics question

2021 · 27 Jul · Shift 1 · Q20

JEE MainChemistryThermodynamicsNumerical+4 / −1
For water at 100 ∘^\circ∘ C and 1 bar, Δ\DeltaΔ vap H −Δ-\Delta−Δ vap U = ‾×\underline{\hspace{2cm}}\times​× 102 J mol −-− 1. (Round off to the Nearest Integer) [Use : R = 8.31 J mol −-− 1 K −-− 1] [Assume volume of H2O(l)H_2O(l)H2​O(l) is much smaller than volume of H2O(g)H_2O(g)H2​O(g). Assume H2O(g)H_2O(g)H2​O(g) treated as an ideal gas]
Numerical answer
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