Doubts
Sign in
12thPass logo
New chatPYQ LibraryDoubtsRank report
Sign in to see Recents
Sign in to save progress →
Doubts
Sign in

Structure of Atom question

2023 · 29 Jan · Shift 1 · Q7
Guest · try one question or challengeGuest · try one question or challenge
  1. PYQ Library
  2. /JEE Main
  3. /Chemistry
  4. /Structure of Atom
  5. /2023 · 29 Jan · Shift 1 · Q7

Structure of Atom question

2023 · 29 Jan · Shift 1 · Q7

JEE MainChemistryStructure of AtomMCQ+4 / −1
The shortest wavelength of hydrogen atom in Lyman series is λ\lambdaλ. The longest wavelength is Balmer series of He +^++ is
  1. A
    36λ5\frac{36\lambda}{5}536λ​
  2. B
    59λ\frac{5}{9\lambda}9λ5​
  3. C
    9λ5\frac{9\lambda}{5}59λ​
  4. D
    5λ9\frac{5\lambda}{9}95λ​
PreviousNext

More from Structure of Atom

  • Assume that the radius of the first Bohr orbit of hydrogen atom is 0.6 Ao​. The radius of the third Bohr orbit of He + is ​ picometer. (Nearest Integer)2023 · Numerical
  • The energy of one mole of photons of radiation of frequency 2×1012 Hz in J mol−1 is ​. (Nearest integer) [Given : h=6.626×10−34 Js NA​=6.022×1023 mol−1…2023 · Numerical
  • Maximum number of electrons that can be accommodated in shell with n=4 are:2023 · MCQ
  • The wave function (Ψ) of 2 s is given by Ψ2 s​=22π​1​(a0​1​)1/2(2−a0​r​)e−r/2a0​ At r=r0​, radial node is formed. Thus, r0​ in…2023 · MCQ
  • Which transition in the hydrogen spectrum would have the same wavelength as the Balmer type transition from n=4 to n=2 of He+ spectrum2023 · MCQ
  • Arrange the following orbitals in decreasing order of energy. A. n=3,l=0, m=0 B. n=4,l=0, m=0 C. n=3,l=1, m=0 D. n=3,l=2, m=1…2023 · MCQ
  • Consider the following pairs of electrons (A) (a) n = 3, l= 1, m1 = 1, ms = +21​(b) n = 3, 1 = 2, m1 = 1, ms = +21​(B) (a) n = 3, l= 2, m1 =− 2, ms = −21​(b) n = 3, l= 2, m1 =− 1, ms = $-{1 \over…2022 · MCQ
  • The energy of one mole of photons of radiation of wavelength 300 nm is (Given : h = 6.63 × 10 − 34 J s, NA = 6.02 × 1023 mol − 1, c = 3 × 108 m s − 1)2022 · MCQ