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Structure of Atom question

2006 · Shift 0 · Q46
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Structure of Atom question

2006 · Shift 0 · Q46

JEE MainChemistryStructure of AtomMCQ+4 / −1
According to Bohr's theory, the angular momentum of an electron in 5th orbit is
  1. A
    10 h/πh/\pih/π
  2. B
    2.5 h/πh/\pih/π
  3. C
    25 h/πh/\pih/π
  4. D
    1.0 h/πh/\pih/π
View written solutionFree

Correct answer: B

  1. Bohr’s quantization of angular momentum

    According to Bohr’s theory, the angular momentum of an electron in the nnnth orbit is: L=nh2πL = \frac{nh}{2\pi}L=2πnh​

  2. For the 5th orbit

    Here, n=5n=5n=5. So, L=5h2πL = \frac{5h}{2\pi}L=2π5h​

  3. Simplify

    5h2π=2.5hπ\frac{5h}{2\pi} = 2.5\frac{h}{\pi}2π5h​=2.5πh​

  4. Match with the options

    • A: 10 h/π10\,h/\pi10h/π ❌
    • B: 2.5 h/π2.5\,h/\pi2.5h/π ✅
    • C: 25 h/π25\,h/\pi25h/π ❌
    • D: 1.0 h/π1.0\,h/\pi1.0h/π ❌

Therefore, the correct answer is Option B.

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