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Some Basic Concepts of Chemistry question

2022 · 25 Jun · Shift 1 · Q15
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Some Basic Concepts of Chemistry question

2022 · 25 Jun · Shift 1 · Q15

JEE MainChemistrySome Basic Concepts of ChemistryNumerical+4 / −1
The number of N atoms in 681 g of C7H5N3O6C_7H_5N_3O_6C7​H5​N3​O6​ is x ×\times× 1021. The value of x is (NA = 6.02 ×\times× 1023 mol −-− 1) (Nearest Integer)
Numerical answer
View written solutionFree

Correct answer: 5418

  1. Find molar mass of C7H5N3O6C_7H_5N_3O_6C7​H5​N3​O6​

M=7(12)+5(1)+3(14)+6(16)M = 7(12) + 5(1) + 3(14) + 6(16)M=7(12)+5(1)+3(14)+6(16)

M=84+5+42+96=227 g mol−1M = 84 + 5 + 42 + 96 = 227\text{ g mol}^{-1}M=84+5+42+96=227 g mol−1

  1. Find number of moles in 681 g

n=681227=3 moln = \frac{681}{227} = 3\text{ mol}n=227681​=3 mol

  1. Find moles of nitrogen atoms

Each molecule of C7H5N3O6C_7H_5N_3O_6C7​H5​N3​O6​ contains 333 nitrogen atoms.

So, in 333 mol of compound, moles of N atoms are:

3×3=9 mol of N atoms3 \times 3 = 9\text{ mol of N atoms}3×3=9 mol of N atoms

  1. Find number of nitrogen atoms

N atoms=9×NA=9×6.02×1023N\text{ atoms} = 9 \times N_A = 9 \times 6.02 \times 10^{23}N atoms=9×NA​=9×6.02×1023

=54.18×1023=5418×1021= 54.18 \times 10^{23} = 5418 \times 10^{21}=54.18×1023=5418×1021

So,

x=5418x = 5418x=5418

  1. Comparison with stored answer

Stored correct answer = 541854185418

This matches our derived answer.

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