JEE MainChemistrySome Basic Concepts of ChemistryNumerical+4 / −1
A 6.50 molal solution of KOH (aq.) has a density of 1.89 g cm 3. The molarity of the solution is mol dm 3. (Round off to the Nearest Integer). [Atomic masses : K : 39.0 u; O : 16.0 u; H : 1.0 u]
Numerical answer
More from Some Basic Concepts of Chemistry
- When 35 mL of 0.15 M lead nitrate solution is mixed with 20 mL of 0.12 M chromic sulphate solution, 10 5 moles of lead sulphate precipitate out. (Round off to the Nearest Integer).2021 · Numerical
- The exact volumes of 1 M solution required to neutralise 50 mL of 1 M solution and 100 mL of 2 M solution, respectively, are :2021 · MCQ
- 15 mL of aqueous solution of in acidic medium completely reacted with 20 mL of 0.03 M aqueous . The molarity of the solution is 10-2 M. (Round off to the Nearest…2021 · Numerical
- The mole fraction of a solute in a 100 molal aqueous solution is 10 2. (Round off to the Nearest Integer). [Given : Atomic masses : H : 1.0 u, O : 16.0 u ]2021 · Numerical
- Consider the above reaction. The percentage yield of amide product is . (Round off to the Nearest Integer). (Given : Atomic mass : C : 12.0 u, H : 1.0 u, N : 14.0 u, O : 16.0 u, Cl : 35.5 u) Includes diagram2021 · Numerical
- grams of 3-Hydroxy propanal (MW = 74) must be dehydrated to produce 7.8 g of acrolein (MW = 56) () if the percentage yield is 64. (Round off to the Nearest Integer). [Given : Atomic masses : C : 12.0 u,…2021 · Numerical
- A reaction of 0.1 mole of Benzylamine with bromomethane gave 23 g of Benzyl trimethyl ammonium bromide. The number of moles of bromomethane consumed in this reaction are n 10 1, when n = . (Round off…2021 · Numerical
- Complete combustion of 3g of ethane gives x 1022 molecules of water. The value of x is . (Round off to the Nearest Integer). [Use : NA = 6.023 1023; Atomic masses in u : C : 12.0; O : 16.0; H :…2021 · Numerical