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Solutions question

2023 · 29 Jan · Shift 2 · Q11
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Solutions question

2023 · 29 Jan · Shift 2 · Q11

JEE MainChemistrySolutionsMCQ+4 / −1

Match List I with List II

List I List II
A. van't Hoff factor, i I. Cryoscopic constant
B. kf\mathrm{k_f}kf​ II. Isotonic solutions
C. Solutions with same osmotic pressure III. Normal molar massAbnormal molar mass\mathrm{\frac{Normal\,molar\,mass}{Abnormal\,molar\,mass}}AbnormalmolarmassNormalmolarmass​
D. Azeotropes IV. Solutions with same composition of vapour above it

Choose the correct answer from the options given below :

  1. A
    A-III, B-I, C-IV, D-II
  2. B
    A-III, B-I, C-II, D-IV
  3. C
    A-III, B-II, C-I, D-IV
  4. D
    A-I, B-III, C-II, D-IV
View written solutionFree

Correct answer: B

  1. Match A: van't Hoff factor, iii

    The van't Hoff factor is defined as i=Normal molar massAbnormal molar massi = \frac{\text{Normal molar mass}}{\text{Abnormal molar mass}}i=Abnormal molar massNormal molar mass​ So, A→IIIA \to IIIA→III

  2. Match B: kfk_fkf​

    kfk_fkf​ denotes the cryoscopic constant. So, B→IB \to IB→I

  3. Match C: Solutions with same osmotic pressure

    Solutions having the same osmotic pressure are called isotonic solutions. So, C→IIC \to IIC→II

  4. Match D: Azeotropes

    Azeotropes are solutions that boil without change in composition, i.e. the vapour has the same composition as the liquid solution. So, D→IVD \to IVD→IV

  5. Final matching

    A−III,  B−I,  C−II,  D−IVA-III,\; B-I,\; C-II,\; D-IVA−III,B−I,C−II,D−IV

  6. Check with options

    This corresponds to Option B.

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