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Solutions question

2023 · 29 Jan · Shift 1 · Q17
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Solutions question

2023 · 29 Jan · Shift 1 · Q17

JEE MainChemistrySolutionsNumerical+4 / −1
Solid Lead nitrate is dissolved in 1 litre of water. The solution was found to boil at 100.15 ∘^\circ∘ C. When 0.2 mol of NaCl is added to the resulting solution, it was observed that the solution froze at −0.8∘-0.8^\circ−0.8∘ C. The solubility product of PbCl 2_22​ formed is ‾\underline{\hspace{2cm}}​×\times× 10 −6^{-6}−6 at 298 K. (Nearest integer) Given : Kb=0.5\mathrm{K_b=0.5}Kb​=0.5 K kg mol −1^{-1}−1 and Kf=1.8\mathrm{K_f=1.8}Kf​=1.8 K kg mol −1^{-1}−1. Assume molality to the equal to molarity in all cases.
Numerical answer
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