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Solutions question

2023 · 31 Jan · Shift 1 · Q20
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Solutions question

2023 · 31 Jan · Shift 1 · Q20

JEE MainChemistrySolutionsNumerical+4 / −1
At 27∘C27^{\circ} \mathrm{C}27∘C, a solution containing 2.5 g2.5 \mathrm{~g}2.5 g of solute in 250.0 mL250.0 \mathrm{~mL}250.0 mL of solution exerts an osmotic pressure of 400 Pa400 \mathrm{~Pa}400 Pa. The molar mass of the solute is ‾g mol−1\underline{\hspace{2cm}}\mathrm{g} \mathrm{~mol}^{-1}​g mol−1(Nearest integer) (Given : R=0.083 L bar K−1 mol−1\mathrm{R}=0.083 \mathrm{~L} \mathrm{~bar} \mathrm{~K}^{-1} \mathrm{~mol}^{-1}R=0.083 L bar K−1 mol−1)
Numerical answer
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