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Redox Reactions question

2025 · 28 Jan · Shift 1 · Q16
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Redox Reactions question

2025 · 28 Jan · Shift 1 · Q16

JEE MainChemistryRedox ReactionsMCQ+4 / −1

Match the List - I with List - II

List - I
(Redox Reaction)		 List - II
(Type of Redox Reaction)
(A) CH4( g)+2O2( g)→ΔCO2( g)+2H2O(l)\begin{aligned} & \mathrm{CH}_{4(\mathrm{~g})}+2 \mathrm{O}_{2(\mathrm{~g})} \xrightarrow{\Delta} \mathrm{CO}_{2(\mathrm{~g})} \\ & +2 \mathrm{H}_2 \mathrm{O}_{(\mathrm{l})}\end{aligned}​CH4( g)​+2O2( g)​Δ​CO2( g)​+2H2​O(l)​​ (I) Disproportionation reaction
(B) 2NaH(s)→Δ2Na(s)+H2( g)2 \mathrm{NaH}_{(\mathrm{s})} \xrightarrow{\Delta} 2 \mathrm{Na}_{(\mathrm{s})}+\mathrm{H}_{2(\mathrm{~g})}2NaH(s)​Δ​2Na(s)​+H2( g)​ (II) Combination reaction
(C) V2O5( s)+5Ca(s)→Δ2 V(s)+5CaO(s)\begin{aligned} & \mathrm{V}_2 \mathrm{O}_{5(\mathrm{~s})}+5 \mathrm{Ca}_{(\mathrm{s})} \xrightarrow{\Delta} 2 \mathrm{~V}_{(\mathrm{s})} \\ & +5 \mathrm{CaO}_{(\mathrm{s})}\end{aligned}​V2​O5( s)​+5Ca(s)​Δ​2 V(s)​+5CaO(s)​​ (III) Decomposition reaction
(D) 2H2O2(aq)⟶Δ2H2O(l)+O2( g)\begin{aligned} & 2 \mathrm{H}_2 \mathrm{O}_{2(\mathrm{aq})} \stackrel{\Delta}{\longrightarrow} 2 \mathrm{H}_2 \mathrm{O}_{(\mathrm{l})}+ \\ & \mathrm{O}_{2(\mathrm{~g})}\end{aligned}​2H2​O2(aq)​⟶Δ​2H2​O(l)​+O2( g)​​ (IV) Displacement reaction

Choose the correct answer from the options given below:

  1. A
    A-III, B-IV, C-I, D-II
  2. B
    A-IV, B-I, C-II, D-III
  3. C
    A-II, B-III, C-I, D-IV
  4. D
    A-II, B-III, C-IV, D-I
View written solutionFree

Correct answer: D

  1. We identify the type of redox reaction for each reaction in List-I.
  1. Reaction (A)

CH4(g)+2O2(g)→ΔCO2(g)+2H2O(l)\mathrm{CH_4(g) + 2O_2(g) \xrightarrow{\Delta} CO_2(g) + 2H_2O(l)}CH4​(g)+2O2​(g)Δ​CO2​(g)+2H2​O(l)

This is the burning of methane.

  • Two reactants combine with oxygen to give products.
  • In redox classification by reaction pattern, this is a combination with oxygen (combustion) type.

So, (A)→(II) Combination reaction(A) \to (II)\text{ Combination reaction}(A)→(II) Combination reaction

  1. Reaction (B)

2NaH(s)→Δ2Na(s)+H2(g)2\mathrm{NaH(s)} \xrightarrow{\Delta} 2\mathrm{Na(s)} + \mathrm{H_2(g)}2NaH(s)Δ​2Na(s)+H2​(g)

A single compound breaks into simpler substances on heating.

So, (B)→(III) Decomposition reaction(B) \to (III)\text{ Decomposition reaction}(B)→(III) Decomposition reaction

  1. Reaction (C)

V2O5(s)+5Ca(s)→Δ2V(s)+5CaO(s)\mathrm{V_2O_5(s) + 5Ca(s) \xrightarrow{\Delta} 2V(s) + 5CaO(s)}V2​O5​(s)+5Ca(s)Δ​2V(s)+5CaO(s)

Here calcium removes oxygen from vanadium oxide:

  • Ca\mathrm{Ca}Ca displaces vanadium from its oxide.
  • This is a displacement redox reaction.

So, (C)→(IV) Displacement reaction(C) \to (IV)\text{ Displacement reaction}(C)→(IV) Displacement reaction

  1. Reaction (D)

2H2O2(aq)→Δ2H2O(l)+O2(g)2\mathrm{H_2O_2(aq)} \xrightarrow{\Delta} 2\mathrm{H_2O(l)} + \mathrm{O_2(g)}2H2​O2​(aq)Δ​2H2​O(l)+O2​(g)

Oxidation state of oxygen in H2O2\mathrm{H_2O_2}H2​O2​ is −1-1−1.

  • In H2O\mathrm{H_2O}H2​O, oxygen is −2-2−2 (reduction)
  • In O2\mathrm{O_2}O2​, oxygen is 000 (oxidation)

The same species undergoes both oxidation and reduction.

So, (D)→(I) Disproportionation reaction(D) \to (I)\text{ Disproportionation reaction}(D)→(I) Disproportionation reaction

  1. Therefore the complete matching is:

A−II,  B−III,  C−IV,  D−IA-II,\; B-III,\; C-IV,\; D-IA−II,B−III,C−IV,D−I

This corresponds to Option D.

  1. Comparison with stored answer

Stored correct answer = D

Our derived answer = D

Hence, they agree.

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