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Periodic Table and Periodicity question

2025 · 3 Apr · Shift 1 · Q2
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Periodic Table and Periodicity question

2025 · 3 Apr · Shift 1 · Q2

JEE MainChemistryPeriodic Table and PeriodicityMCQ+4 / −1
Which of the following statements are correct? A. The process of adding an electron to a neutral gaseous atom is always exothermic. B. The process of removing an electron from an isolated gaseous atom is always endothermic. C. The 1st 1^{\text {st }}1st  ionization energy of boron is less than that of beryllium. D. The electronegativity of C is 2.5 in CH4\mathrm{CH}_4CH4​ and CCl4\mathrm{CCl}_4CCl4​ E. Li is the most electropositive among elements of group I. Choose the correct answer from the options given below:
  1. A
    A, C and D Only
  2. B
    B and C Only
  3. C
    B and D Only
  4. D
    B, C and E Only
View written solutionFree

Correct answer: B

  1. Check statement A: "The process of adding an electron to a neutral gaseous atom is always exothermic."

    This refers to electron gain enthalpy / electron affinity.

    It is not always exothermic. For some atoms, especially noble gases and some alkaline earth metals / nitrogen-like stable configurations, adding an electron can require energy, i.e. it can be endothermic.

    Hence, A is false.

  2. Check statement B: "The process of removing an electron from an isolated gaseous atom is always endothermic."

    This is the definition of ionization enthalpy.

    Removing an electron from an isolated gaseous atom always requires energy input: X(g)→X+(g)+e−X(g) \rightarrow X^+(g) + e^-X(g)→X+(g)+e− so the process is always endothermic.

    Hence, B is true.

  3. Check statement C: "The 1st1^{\text{st}}1st ionization energy of boron is less than that of beryllium."

    Electronic configurations: Be:1s22s2\text{Be}: 1s^2 2s^2Be:1s22s2 B:1s22s22p1\text{B}: 1s^2 2s^2 2p^1B:1s22s22p1

    The electron removed from boron is a 2p2p2p electron, which is higher in energy and less tightly held than the 2s2s2s electron in Be. Therefore, IE1(B)<IE1(Be)IE_1(\text{B}) < IE_1(\text{Be})IE1​(B)<IE1​(Be)

    Hence, C is true.

  4. Check statement D: "The electronegativity of C is 2.5 in CH4\mathrm{CH_4}CH4​ and CCl4\mathrm{CCl_4}CCl4​."

    Electronegativity is not a fixed constant in all compounds; it depends on the chemical environment, hybridization, and bonded atoms. Thus saying carbon has exactly the same electronegativity value 2.52.52.5 in both CH4\mathrm{CH_4}CH4​ and CCl4\mathrm{CCl_4}CCl4​ is not correct in this context.

    Hence, D is false.

  5. Check statement E: "Li is the most electropositive among elements of group I."

    Electropositivity increases down the group. Among alkali metals, the lower elements are more electropositive than Li.

    Therefore, Li is not the most electropositive.

    Hence, E is false.

  6. Collect correct statements

    • A: False
    • B: True
    • C: True
    • D: False
    • E: False

    So the correct set is: B and C only\boxed{\text{B and C only}}B and C only​

  7. Match with options

    Option B = B and C Only.

Therefore, the correct answer is Option B.

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